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Question
ethan is proving that the slope between any two points on a straight line is the same. he has already proved that triangles 1 and 2 are similar. drag statements and reasons to complete the proof. slope cannot be a ratio. definition of slope slope from p to q = \\(\frac{f}{e}\\) f - e = f - e \\(\frac{f}{e}=\frac{f}{e}\\) slope from q to r = \\(\frac{f}{e}\\) reason: definition of slope
Step1: Recall the definition of slope
The slope between two points \((x_1,y_1)\) and \((x_2,y_2)\) is given by \(m=\frac{y_2 - y_1}{x_2 - x_1}\). For the slope from \(P\) to \(Q\) and from \(Q\) to \(R\), we use the properties of similar triangles. Since triangles \(1\) and \(2\) are similar, the ratios of their corresponding sides are equal.
Step2: Use the property of similar - triangles
If two triangles are similar, then \(\frac{E}{F}=\frac{E'}{F'}\) (corresponding - side - ratio property of similar triangles).
Step3: Apply the slope - formula and similar - triangle property
The slope from \(P\) to \(Q\) is \(\frac{E}{F}\) (by the definition of slope, where \(E\) is the vertical change and \(F\) is the horizontal change) and the slope from \(Q\) to \(R\) is \(\frac{E'}{F'}\). Since \(\frac{E}{F}=\frac{E'}{F'}\) (because of similar triangles), and the slope from \(P\) to \(Q\) and from \(Q\) to \(R\) are calculated using the ratio of vertical - change to horizontal - change (definition of slope).
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Statement: Slope from \(Q\) to \(R=\frac{E'}{F'}\)
Reason: \(\frac{E}{F}=\frac{E'}{F'}\)