Question

er and area using the distance formula
i(3,9)
w(16,4)
q(16,3)
$d = sqrt{(-13)^2+(5)^2}$
$d = $

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, for points $I(3,9)$ and $W(16,4)$, $x_1 = 3,y_1=9,x_2 = 16,y_2 = 4$. Then $x_2 - x_1=16 - 3=13$ and $y_2 - y_1=4 - 9=- 5$.

Step2: Substitute values into formula

We have $d=\sqrt{(13)^2+(-5)^2}=\sqrt{169 + 25}$.

Step3: Calculate the sum inside square - root

$169+25 = 194$. So $d=\sqrt{194}\approx13.93$.

Answer:

$\sqrt{194}\approx13.93$