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Question
elena wants to create a second triangular garden that is similar to the first, but the diagonal path must be exactly 15 ft long. if the shorter leg of the new garden is 9 ft, what must be the length of the longer leg? the length of the longer leg is ft. hide math input basic symbols greek other
Step1: Apply Pythagorean theorem
Let the longer leg be \(x\). For a right - triangle (garden with diagonal as hypotenuse), by Pythagorean theorem \(a^{2}+b^{2}=c^{2}\), where \(a = 9\) (shorter leg), \(b=x\) (longer leg), \(c = 15\) (hypotenuse). So \(9^{2}+x^{2}=15^{2}\).
Step2: Simplify the equation
\(81+x^{2}=225\). Then \(x^{2}=225 - 81\).
Step3: Calculate \(x^{2}\)
\(x^{2}=144\).
Step4: Solve for \(x\)
Take square root of both sides, \(x=\sqrt{144}\), \(x = 12\).
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