Question

4.
domain:
range:
function?
5.
domain:
range:
function?
6.
domain:
range:
function?
topic 2: equations as functions
directions: given the function and its domain, find the range.

1. $y = 5x + 11$; domain = {-4, -1, 0}
2. $y = 9 - \frac{1}{2}x$; domain = {-6, -2, 8}

directions: complete each function table, then graph.

1. $y = -2x + 7$

\

$$\begin{tabular}{|c|c|} \\hline $x$ & $y$ \\\\ \\hline 0 & \\\\ \\hline 3 & \\\\ \\hline 4 & \\\\ \\hline 6 & \\\\ \\hline \\end{tabular}$$

1. $y = -x - 4$

\

$$\begin{tabular}{|c|c|} \\hline $x$ & $y$ \\\\ \\hline -8 & \\\\ \\hline -5 & \\\\ \\hline 1 & \\\\ \\hline 3 & \\\\ \\hline \\end{tabular}$$

© gina wilson (all things algebra®, llc), 2016

Explanation:

Problem 7

Step1: Substitute \( x = -4 \) into \( y = 5x + 11 \)

\( y = 5(-4) + 11 = -20 + 11 = -9 \)

Step2: Substitute \( x = -1 \) into \( y = 5x + 11 \)

\( y = 5(-1) + 11 = -5 + 11 = 6 \)

Step3: Substitute \( x = 0 \) into \( y = 5x + 11 \)

\( y = 5(0) + 11 = 0 + 11 = 11 \)

Step1: Substitute \( x = -6 \) into \( y = 9 - \frac{1}{2}x \)

\( y = 9 - \frac{1}{2}(-6) = 9 + 3 = 12 \)

Step2: Substitute \( x = -2 \) into \( y = 9 - \frac{1}{2}x \)

\( y = 9 - \frac{1}{2}(-2) = 9 + 1 = 10 \)

Step3: Substitute \( x = 8 \) into \( y = 9 - \frac{1}{2}x \)

\( y = 9 - \frac{1}{2}(8) = 9 - 4 = 5 \)

Step1: Substitute \( x = 0 \) into \( y = -2x + 7 \)

\( y = -2(0) + 7 = 7 \)

Step2: Substitute \( x = 3 \) into \( y = -2x + 7 \)

\( y = -2(3) + 7 = -6 + 7 = 1 \)

Step3: Substitute \( x = 4 \) into \( y = -2x + 7 \)

\( y = -2(4) + 7 = -8 + 7 = -1 \)

Step4: Substitute \( x = 6 \) into \( y = -2x + 7 \)

\( y = -2(6) + 7 = -12 + 7 = -5 \)

Answer:

Range: \(\{-9, 6, 11\}\)

Problem 8