QUESTION IMAGE
Question
determine which segment is shortest in the diagram. note that the figure to the right is not drawn to scale. the shortest segment in the diagram is
Step1: Find angles in \(\triangle YXZ\)
In \(\triangle YXZ\), we know \(\angle YZX = 180^{\circ}-(38^{\circ}+117^{\circ})=25^{\circ}\) (using the angle - sum property of a triangle \(\angle A+\angle B+\angle C = 180^{\circ}\)).
Step2: Find angles in \(\triangle XWZ\)
In \(\triangle XWZ\), \(\angle XZW=180^{\circ}-(119^{\circ}+42^{\circ}) = 19^{\circ}\) (using the angle - sum property of a triangle \(\angle A+\angle B+\angle C = 180^{\circ}\)).
Step3: Recall the side - angle relationship
In a triangle, the shorter side is opposite the smaller angle.
- In \(\triangle YXZ\), sides are \(XY\), \(YZ\), \(XZ\) with opposite angles \(\angle YZX = 25^{\circ}\), \(\angle YXZ=38^{\circ}\), \(\angle XYZ = 117^{\circ}\) respectively. So \(XZ
- In \(\triangle XWZ\), sides are \(XW\), \(WZ\), \(XZ\) with opposite angles \(\angle XZW = 19^{\circ}\), \(\angle WXZ=119^{\circ}\), \(\angle XWZ = 42^{\circ}\) respectively. So \(XZ
- In \(\triangle XWZ\), sides are \(XW\), \(WZ\), \(XZ\) with opposite angles \(\angle XZW = 19^{\circ}\), \(\angle WXZ=119^{\circ}\), \(\angle XWZ = 42^{\circ}\) respectively. So \(XZ
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