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consider the lines through the origin (x), (m), (n), (ell), and (y), wh…

Question

consider the lines through the origin (x), (m), (n), (ell), and (y), where (x) represents the (x)-axis, (y) represents the (y)-axis, (m) has angle (\theta) from the positive (x)-axis, (n) has angle (phi) from the positive (x)-axis, and (ell) has angle (gamma) from the positive (x)-axis, with (0 < \theta < phi < gamma < 90^{circ}). it is possible to write the product (r_y r_{ell} r_n r_m r_x) as a single reflection (r_k). determine the angle between the line (k) and the positive (x)-axis in terms of angles (\theta), (phi), and (gamma).

Explanation:

⚡ Using what you learned: Compositions of Transformations

Step 1: Represent reflections as matrix transformations

Let \( r_{\alpha} \) denote the reflection across a line through the origin making an angle \( \alpha \) with the positive \( x \)-axis. The matrix representing this reflection is:

$$ [r_{\alpha}] = LATEXBLOCK0 $$

The given lines have the following angles with the positive \( x \)-axis:

  • Line \( x \): angle \( 0 \)
  • Line \( m \): angle \( \theta \)
  • Line \( n \): angle \( \phi \)
  • Line \( \ell \): angle \( \gamma \)
  • Line \( y \): angle \( 90^\circ \)

Step 2: Compose the reflections

The composition of transformations is applied from right to left: \( r_y \circ r_{\ell} \circ r_n \circ r_m \circ r_x \).

Using the property that the composition of two reflections \( r_{\beta} \circ r_{\alpha} \) is a rotation by \( 2(\beta - \alpha) \):

$$ R(\delta) = LATEXBLOCK1 $$

We group the composition as:

$$ (r_y \circ r_{\ell}) \circ (r_n \circ r_m) \circ r_x $$
  • \( r_n \circ r_m \) is a rotation by \( 2(\phi - \theta) \).
  • \( r_y \circ r_{\ell} \) is a rotation by \( 2(90^\circ - \gamma) \).

Combining these rotations:

$$ (r_y \circ r_{\ell}) \circ (r_n \circ r_m) = R(2(90^\circ - \gamma) + 2(\phi - \theta)) = R(180^\circ - 2\gamma + 2\phi - 2\theta) $$

Step 3: Apply the final reflection

Now, compose this rotation with the remaining reflection \( r_x \) (where the angle is \( 0 \)):

$$ r_k = R(180^\circ - 2\gamma + 2\phi - 2\theta) \circ r_x $$

A rotation by \( \delta \) composed with a reflection across a line at angle \( 0 \) results in a reflection across a line at angle \( \frac{\delta}{2} \):

$$ \text{Angle of line } k = \frac{180^\circ - 2\gamma + 2\phi - 2\theta}{2} = 90^\circ - \gamma + \phi - \theta $$

Answer:

The angle between the line \( k \) and the positive \( x \)-axis is:

$$ 90^\circ - \gamma + \phi - \theta $$