QUESTION IMAGE
Question
consider the diagram.
what is the length of segment ab?
18
9
25
7
Step1: Use the Hypotenuse - Leg (HL) Congruence Theorem
Since the line \(l\) is the perpendicular bisector of \(AC\), \(\triangle ABD\cong\triangle CBD\) (by HL theorem: \(BD = BD\) (common side), \(AD = CD\) (not directly used here, but \(AB = BC\) as a result of congruence).
Step2: Apply the Pythagorean Theorem in \(\triangle ABD\)
Let \(AB=x\). In right - triangle \(ABD\), by the Pythagorean theorem \(AD^{2}=AB^{2}+BD^{2}\). Wait, no, we know that \(AD = 16\), \(BD\) is not needed. Since \(AB = BC\) (from congruent triangles \(\triangle ABD\) and \(\triangle CBD\)) and in right - triangle \(ABD\) (or \(CBD\)), using the Pythagorean theorem in a wrong way. Wait, actually, since \(AB = BC\) (because the perpendicular bisector property: any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. Here \(D\) is on the perpendicular bisector of \(AC\), but we can also use the fact that \(\triangle ABD\) and \(\triangle CBD\) are right - triangles. \(AD = 16\), \(CD\) (not relevant here), \(BC = 9\) (wait no, no. Wait, the right - triangle is \(ABD\) where \(AD = 16\), and if we assume \(AB=x\) and \(BD\) is common. But wait, the key is that \(AB = BC\) (perpendicular bisector property: a point \(B\) on the perpendicular bisector of \(AC\) implies \(AB = BC\)). Wait, no, the perpendicular bisector of \(AC\) is the line \(l\). So \(AB=BC\). But in the figure, if we consider the right - triangle \(ABD\) (assuming \(BD\) is the height). Wait, no, the correct approach:
Since \(AB = BC\) (by the property of the perpendicular bisector of a segment: if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. Here \(B\) is on the perpendicular bisector of \(AC\)), and we use the Pythagorean theorem in \(\triangle ABD\). Let \(AB = x\), then in right - triangle \(ABD\), \(AD^{2}=AB^{2}+BD^{2}\). Wait, no, wait, the correct formula: In right - triangle \(ABD\), \(AD = 16\), and if we assume \(AB=x\) and \(BD\) is not needed. Wait, no, the figure shows that \(AB = BC\) (from the perpendicular bisector property). Let's use the Pythagorean theorem in \(\triangle ABD\): \(AD^{2}=AB^{2}+BD^{2}\). No, wait, the correct way is:
Since \(AB = BC\) (perpendicular bisector property), and in right - triangle \(ABD\) (assuming \(BD\) is the height). Wait, no, the key is that \(AB = BC\) (a point on the perpendicular bisector of a segment is equidistant from the segment's endpoints). So \(AB = 9\) (because \(BC = 9\) as given in the problem's visual (the segment \(BC\) has length \(9\))).
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