consider the diagram and proof by contradiction. given: △abc with $\overline{ab} \cong \overline{ac}$ diagram of triangle abc with ab and ac marked congruent since it is given that $\overline{ab} \cong \overline{ac}$, it must also be true that ab = ac. assume $\angle b$ and $\angle c$ are not congruent. then the measure of one angle is greater than the other. if $m\angle b m\angle c$, then ac ab because of the triangle parts relationship theorem. for the same reason, if $m\angle b

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consider the diagram and proof by contradiction. given: △abc with $\overline{ab} \cong \overline{ac}$ diagram of triangle abc with ab and ac marked congruent since it is given that $\overline{ab} \cong \overline{ac}$, it must also be true that ab = ac. assume $\angle b$ and $\angle c$ are not congruent. then the measure of one angle is greater than the other. if $m\angle b > m\angle c$, then ac > ab because of the triangle parts relationship theorem. for the same reason, if $m\angle b < m\angle c$, then ac < ab. this is a contradiction to what is given. therefore, it can be concluded that ______. $\bigcirc$ ab ≠ ac $\bigcirc$ $\angle b \cong \angle c$ $\bigcirc$ abc is not a triangle $\bigcirc$ $\angle a \cong \angle b \cong \angle c$

Accepted Answer

# Brief Explanations:
The proof uses contradiction: assuming ∠B ≅ ∠C is false leads to AC ≠ AB, conflicting with given AB ≅ AC. Thus, the assumption is wrong.

# Answer:
B. ∠B ≅ ∠C

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