QUESTION IMAGE
Question
- in \\( \triangle a b c, \angle a \\) and \\( \angle c \\) are congruent, and the measure of \\( \angle b \\) is \\( 143.6 ^ { \circ } \\). what is the measure of \\( \angle a \\)?
f. \\( 18.2 ^ { \circ } \\)
g. \\( 36.4 ^ { \circ } \\)
h. \\( 71.8 ^ { \circ } \\)
j. \\( 143.6 ^ { \circ } \\)
- which of the following expressions is equivalent to \\( x ^ { 2 } - x - 30 \\)?
a. \\( ( x + 3 ) ( x - 10 ) \\)
b. \\( ( x + 6 ) ( x - 5 ) \\)
c. \\( ( x - 6 ) ( x + 5 ) \\)
d. \\( ( x - 15 ) ( x - 15 ) \\)
- which of the following matrices is equal to \\( 5 \left \
\
ight \\)?
f. \\( - 20 - 15 \\)
g. \\( \left \
\
ight \\)
h. \\( \left \
\
ight \\)
j. \\( \left \
\
ight \\)
Step1: Triangle angle sum property
The sum of angles in a triangle is \(180^{\circ}\). Let \(\angle A=\angle C = x\). Then \(x + x+143.6^{\circ}=180^{\circ}\).
Step2: Simplify the equation
Combine like - terms: \(2x=180^{\circ}- 143.6^{\circ}\). So \(2x = 36.4^{\circ}\).
Step3: Solve for \(x\)
Divide both sides by 2: \(x=\frac{36.4^{\circ}}{2}=18.2^{\circ}\).
Step1: Expand the options
For option B: \((x + 6)(x - 5)=x^{2}-5x+6x - 30\).
Step2: Combine like - terms
\(x^{2}-5x+6x - 30=x^{2}+x - 30\).
Step1: Scalar multiplication of a matrix
If \(A=
\) and \(k\) is a scalar, then \(kA=
\). Here \(k = 5\), \(a=-4\), \(b = 2\), \(c = 0\), \(d=-5\).
Step2: Calculate each element
\(5\times(-4)=-20\), \(5\times2 = 10\), \(5\times0=0\), \(5\times(-5)=-25\). So \(5
=
\).
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F. \(18.2^{\circ}\)