Question

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given the rectangle abcd as shown, find ac if ao = 9x - 1 and do = 6x + 17
(1 point)
ac =
check answer remaining attempts 3

Explanation:

Step1: Use the property of rectangle diagonals

In a rectangle, the diagonals are equal and bisect each other. So \(AO = DO\).

$$9x - 1=6x + 17$$

Step2: Solve the equation for \(x\)

Subtract \(6x\) from both sides:

$$9x-6x - 1=6x-6x + 17$$

$$3x-1 = 17$$

Add \(1\) to both sides:

$$3x-1 + 1=17 + 1$$

$$3x=18$$

Divide both sides by \(3\):

$$x=\frac{18}{3}=6$$

Step3: Find the length of \(AO\)

Substitute \(x = 6\) into \(AO=9x - 1\):

$$AO=9\times6-1=54 - 1=53$$

Step4: Calculate \(AC\)

Since \(AC = 2AO\) (diagonals bisect each other in a rectangle)

$$AC=2\times53 = 106$$

Answer:

\(106\)