Question

in $delta jkl$, $j = 79$ cm, $k = 74$ cm and $l = 65$ cm. find the area of $delta jkl$ to the nearest square centimeter.

Explanation:

Step1: Calculate the semi - perimeter

The semi - perimeter $s$ of a triangle with side lengths $a$, $b$, and $c$ is given by $s=\frac{a + b + c}{2}$. Here, $a = 79$, $b = 74$, $c = 65$, so $s=\frac{79+74 + 65}{2}=\frac{218}{2}=109$ cm.

Step2: Use Heron's formula

Heron's formula for the area $A$ of a triangle is $A=\sqrt{s(s - a)(s - b)(s - c)}$. Substitute $s = 109$, $a = 79$, $b = 74$, $c = 65$ into the formula:

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Answer:

$2244$ cm²