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circle d is shown with the measures of the minor arcs. which angles are…

Question

circle d is shown with the measures of the minor arcs.
which angles are congruent?
∠gdf and ∠hdg
∠edh and ∠fdg
∠gdh and ∠edh
∠fde and ∠gdh

Explanation:

Step1: Recall Central Angle Theorem

The measure of a central angle is equal to the measure of its intercepted arc. So, we need to find the measures of each central angle by their intercepted arcs.

Step2: Analyze Each Option

  • For \(\angle GDF\) and \(\angle HDG\): Arc \(GF = 115^\circ\), arc \(HG=65^\circ\). So \(\angle GDF = 115^\circ\), \(\angle HDG = 65^\circ\). Not congruent.
  • For \(\angle EDH\) and \(\angle FDG\): Arc \(EH = 65^\circ\), so \(\angle EDH = 65^\circ\). Arc \(FG = 115^\circ\)? Wait, no, arc \(HG = 65^\circ\), arc \(GF = 115^\circ\), arc \(EH=65^\circ\), arc \(EF = 115^\circ\). Wait, \(\angle FDG\): intercepted arc \(FG\)? No, \(\angle FDG\) intercepts arc \(FG\)? Wait, no, let's re - check. \(\angle EDH\) intercepts arc \(EH\) (measure \(65^\circ\)). \(\angle FDG\): Let's see, arc \(FG\) is \(115^\circ\)? No, wait the arcs: \(EH = 65^\circ\), \(HG = 65^\circ\), \(GF = 115^\circ\), \(FE=115^\circ\). Wait, \(\angle FDG\): The central angle \(\angle FDG\) intercepts arc \(FG\) which is \(115^\circ\)? No, that's not right. Wait, maybe I made a mistake. Wait, \(\angle EDH\): intercepted arc \(EH = 65^\circ\), so \(\angle EDH=65^\circ\). \(\angle FDG\): Wait, what about \(\angle FDE\)? No, let's check the third option: \(\angle GDH\) and \(\angle EDH\). \(\angle GDH\) intercepts arc \(HG = 65^\circ\), so \(\angle GDH = 65^\circ\). \(\angle EDH\) intercepts arc \(EH = 65^\circ\), so \(\angle EDH=65^\circ\). Wait, no, wait the fourth option: \(\angle FDE\) and \(\angle GDH\). \(\angle FDE\) intercepts arc \(FE = 115^\circ\), \(\angle GDH\) intercepts arc \(HG = 65^\circ\). No. Wait, wait the correct one: \(\angle EDH\) (intercepts \(EH = 65^\circ\)) and \(\angle GDH\) (intercepts \(HG = 65^\circ\))? Wait, no, the third option is \(\angle GDH\) and \(\angle EDH\). Wait, \(\angle GDH\) is central angle for arc \(HG\) ( \(65^\circ\)), \(\angle EDH\) is central angle for arc \(EH\) ( \(65^\circ\)). So they are both \(65^\circ\). Wait, but also, let's check the fourth option: \(\angle FDE\) and \(\angle GDH\). \(\angle FDE\) intercepts arc \(FE = 115^\circ\), \(\angle GDH\) intercepts arc \(HG = 65^\circ\). No. Wait, the second option: \(\angle EDH\) and \(\angle FDG\): Wait, maybe I messed up the arcs. Wait, arc \(EH = 65^\circ\), so \(\angle EDH = 65^\circ\). Arc \(FG\): Wait, no, arc \(HG = 65^\circ\), arc \(GF = 115^\circ\), arc \(EF = 115^\circ\), arc \(EH = 65^\circ\). So \(\angle FDG\): Let's see, the central angle \(\angle FDG\) intercepts arc \(FG\) which is \(115^\circ\)? No, that can't be. Wait, maybe the correct pair is \(\angle GDH\) and \(\angle EDH\)? Wait, no, let's re - examine the diagram. The arcs: \(EH = 65^\circ\), \(HG = 65^\circ\), \(GF = 115^\circ\), \(FE = 115^\circ\). So central angles: \(\angle EDH\) (arc \(EH\)) \(= 65^\circ\), \(\angle GDH\) (arc \(HG\)) \(= 65^\circ\), \(\angle FDG\) (arc \(FG\)) \(= 115^\circ\), \(\angle FDE\) (arc \(FE\)) \(= 115^\circ\), \(\angle GDF\) (arc \(GF\)) \(= 115^\circ\), \(\angle EDG\)? Wait, the fourth option: \(\angle FDE\) and \(\angle GDH\). \(\angle FDE\) is \(115^\circ\) (arc \(FE\)), \(\angle GDH\) is \(65^\circ\) (arc \(HG\)). Not congruent. The third option: \(\angle GDH\) (\(65^\circ\)) and \(\angle EDH\) (\(65^\circ\)): Wait, but let's check the second option again. Wait, maybe I made a mistake. Wait, \(\angle EDH\) (arc \(EH = 65^\circ\)) and \(\angle FDG\): Wait, no, \(\angle FDG\) intercepts arc \(FG\) which is \(115^\circ\)? No, that's not. Wait, the correct answer is \(\angle GDH\) and \(\angle EDH\)? Wait, no, the third option is \(\angle GDH\)…

Answer:

\(\angle GDH\) and \(\angle EDH\) (i.e., the option " \(\angle GDH\) and \(\angle EDH\)")