Question

1. in circle o with radius of length 10 cm, central angle poq intercepts qp. find, to the nearest tenth, the radian measure of poq if qp = 40 cm.

Explanation:

Step1: Recall the arc - length formula

The formula for the length of an arc \(s = r\theta\), where \(s\) is the arc - length, \(r\) is the radius of the circle, and \(\theta\) is the radian measure of the central angle.

Step2: Solve for \(\theta\)

Given \(s = 40\) cm and \(r = 10\) cm. From \(s=r\theta\), we can solve for \(\theta\) by \(\theta=\frac{s}{r}\).
Substitute \(s = 40\) and \(r = 10\) into the formula: \(\theta=\frac{40}{10}\)

Answer:

\(4.0\) radians