Question

cc8 homework

1. find the area of a rectangle with points at (-8,5), (2,5), (2,-3) and (-8,-3).

Explanation:

Step1: Find the length of the rectangle

The length can be found by calculating the distance between two points with the same y - coordinate. Using the distance formula for two points $(x_1,y)$ and $(x_2,y)$ which is $d = |x_2 - x_1|$. For points $(-8,5)$ and $(2,5)$, the length $l=|2-(-8)|=|2 + 8| = 10$.

Step2: Find the width of the rectangle

The width can be found by calculating the distance between two points with the same x - coordinate. Using the distance formula for two points $(x,y_1)$ and $(x,y_2)$ which is $d=|y_2 - y_1|$. For points $(2,5)$ and $(2,-3)$, the width $w = |5-(-3)|=|5 + 3|=8$.

Step3: Calculate the area of the rectangle

The area formula of a rectangle is $A=l\times w$. Substituting $l = 10$ and $w = 8$ into the formula, we get $A=10\times8 = 80$.

Answer:

80