Question

ashley is flying a kite, holding her hands a distance of 3.25 feet above the ground and letting all the kites string out. she measures the angle of elevation from her hand to the kite to be 22°. if the string from the kite to her hand is 85 feet long, how many feet is the kite above the ground? round your answer to the nearest tenth of a foot if necessary.

Explanation:

Step1: Use the sine function

The height of the kite above the hand - level is calculated by \(h = 85\times\sin(22^{\circ})\).

Step2: Calculate the total height

The total height of the kite above the ground \(H=3.25 + 85\times\sin(22^{\circ})\).
We know that \(\sin(22^{\circ})\approx0.3746\).
Then \(85\times\sin(22^{\circ})=85\times0.3746 = 31.841\).
And \(H=3.25+31.841=35.091\approx35.1\).

Answer:

\(35.1\)