Question

answer the questions below.
(a) the perimeter of a rectangular parking lot is 316 m.
if the length of the parking lot is 97 m, what is its width?
width of the parking lot: m
(b) the area of a rectangular pool is 4472 m².
if the width of the pool is 52 m, what is its length?
length of the pool: m

Explanation:

Part (a)

Step1: Recall rectangle perimeter formula

The perimeter \( P \) of a rectangle is given by \( P = 2(l + w) \), where \( l \) is length and \( w \) is width. We know \( P = 316 \) m and \( l = 97 \) m. First, divide the perimeter by 2: \( \frac{P}{2}=l + w \). So, \( \frac{316}{2}=97 + w \).

Step2: Solve for width

Calculate \( \frac{316}{2}=158 \). Then, \( 158 = 97 + w \). Subtract 97 from both sides: \( w = 158 - 97 = 61 \).

Step1: Recall rectangle area formula

The area \( A \) of a rectangle is \( A = l\times w \), where \( l \) is length and \( w \) is width. We know \( A = 4472 \) \( m^2 \) and \( w = 52 \) m. So, \( l=\frac{A}{w} \).

Step2: Solve for length

Substitute the values: \( l=\frac{4472}{52} = 86 \).

Answer:

61

Part (b)