Question

5 - 2 altitudes of triangles practice
use the information in the figure below to solve for x.
bt is an altitude
90
29
45
180

Explanation:

Step1: Recall the property of altitude

An altitude of a triangle is perpendicular to the opposite side. So, \( \angle BTA = 90^{\circ}\), and \(3x + 3=90\) (since \(BT\) is an altitude and forms a right - angle with \(CA\)).

Step2: Solve the equation for \(x\)

Subtract 3 from both sides of the equation \(3x + 3=90\):
\(3x=90 - 3\)
\(3x=87\)
Divide both sides by 3: \(x=\frac{87}{3}\)
\(x = 29\)

Answer:

29