Question

△abc ≅ △jkl
provide answers accurate to the nearest hundredth.
x =
jl =

Explanation:

Step1: Solve for \( x \)

Since \( \triangle ABC \cong \triangle JKL \), corresponding angles are equal. So \( \angle A = \angle J \).
\( 3x + 5 = 17 \)
Subtract 5 from both sides: \( 3x = 17 - 5 = 12 \)
Divide by 3: \( x = \frac{12}{3} = 4 \)

Step2: Solve for \( y \)

Corresponding sides are equal, so \( AB = JK \).
\( 17 = 5y - 9 \)
Add 9 to both sides: \( 5y = 17 + 9 = 26 \)
Divide by 5: \( y = \frac{26}{5} = 5.2 \)

Step3: Find \( JL \)

\( JL = 6y \), substitute \( y = 5.2 \)
\( JL = 6 \times 5.2 = 31.2 \)

Answer:

\( x = 4.00 \)
\( JL = 31.20 \)