Question

16/16
calculate
7.34
6.23
5.19
5.56

Explanation:

Step1: Apply Pythagorean theorem

$$a^{2}+b^{2}=c^{2}$$, where \(c = 6\), \(a=3\), find \(b\). So \(b=\sqrt{c^{2}-a^{2}}\)

Step2: Substitute values

Substitute \(c = 6\), \(a = 3\) into the formula: \(b=\sqrt{6^{2}-3^{2}}=\sqrt{36 - 9}=\sqrt{27}\approx5.196\approx5.19\)

Answer:

\(5.19\)