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Question
- $\triangle jklcong\triangle mnp$. $mangle l=x^{2}+10$ and $mangle p = 2x^{2}+1$. what is the $mangle l$?
Step1: Use the property of congruent triangles
Since \(\triangle JKL\cong\triangle MNP\), then \(\angle L\cong\angle P\). So \(m\angle L = m\angle P\).
$$x^{2}+10=2x^{2}+1$$
Step2: Solve the equation for \(x^{2}\)
Subtract \(x^{2}\) from both sides:
$$10=x^{2}+1$$
Subtract \(1\) from both sides:
$$x^{2}=9$$
Step3: Find \(m\angle L\)
Substitute \(x^{2} = 9\) into \(m\angle L=x^{2}+10\)
$$m\angle L=9 + 10=19$$
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\(19\)