QUESTION IMAGE
Question
- there is a diagram with intersecting lines and angles: 49°, (3x)°, (7x - 23)°, and (11y - 1)° with lines l and m.
Step1: Identify angle relationship
The angles \(49^\circ\), \(3x^\circ\), and \(7x - 23^\circ\) form a triangle? Wait, no, actually, looking at the vertical angles or linear pairs? Wait, the angle \(7x - 23\) and the sum of \(49 + 3x\) should be equal because they are vertical angles? Wait, let's see: the three angles at the intersection: \(49^\circ\), \(3x^\circ\), and the angle adjacent to \(7x - 23\) – actually, the angle \(7x - 23\) and the angle formed by \(49 + 3x\) are vertical angles, so they should be equal. So:
\(7x - 23 = 49 + 3x\)
Step2: Solve for x
Subtract \(3x\) from both sides:
\(7x - 3x - 23 = 49\)
\(4x - 23 = 49\)
Add 23 to both sides:
\(4x = 49 + 23\)
\(4x = 72\)
Divide by 4:
\(x = \frac{72}{4} = 18\)
Step3: Find angle for y
Now, since lines \(l\) and \(m\) are parallel? Wait, the angle \(3x\) (when \(x = 18\), \(3x = 54^\circ\)) and \(11y - 1\) should be equal because they are corresponding angles (since \(l\) and \(m\) are parallel, as the transversal creates equal angles). Wait, first, find \(3x\): \(3(18) = 54^\circ\). Then, \(11y - 1 = 54\)? Wait, no, wait: the angle \(49 + 3x = 49 + 54 = 103\)? Wait, no, earlier step: Wait, maybe I made a mistake. Wait, the angle \(7x - 23\) when \(x = 18\) is \(7(18) - 23 = 126 - 23 = 103^\circ\). Then, the angle \(49 + 3x\) should be \(103\), so \(49 + 3x = 103\), so \(3x = 54\), \(x = 18\), which matches. Now, the angle \(3x = 54^\circ\) and \(11y - 1\) are corresponding angles (since \(l\) and \(m\) are parallel), so:
\(11y - 1 = 54\)
Add 1 to both sides:
\(11y = 55\)
Divide by 11:
\(y = 5\)
Wait, but maybe the problem is to find x and y? Let's check again.
Wait, first, solving for x:
\(7x - 23 = 49 + 3x\)
\(7x - 3x = 49 + 23\)
\(4x = 72\)
\(x = 18\)
Then, the angle \(3x = 54^\circ\), and since \(l\) and \(m\) are parallel, the angle \(11y - 1\) is equal to \(3x\) (corresponding angles), so:
\(11y - 1 = 54\)
\(11y = 55\)
\(y = 5\)
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\(x = 18\), \(y = 5\) (assuming the problem is to find x and y; if only x, then \(x = 18\))