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10 given: \\(\overline{km} \cong \overline{nm}\\), \\(\overline{lk} \cong \overline{ln}\\) prove: \\(\triangle lkm \cong \triangle lnm\\) \\(\
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\\) 11 given: \\(\overline{ad} \cong \overline{ab}\\), \\(\overline{ac}\\) bisects \\(\angle dab\\) prove: \\(\triangle adc \cong \triangle abc\\) \\(\
$$\begin{array}{|c|c|} \\hline \\text{statements} & \\text{reasons} \\\\ \\hline 1. & 1. \\\\ \\hline 2. & 2. \\\\ \\hline 3. & 3. \\\\ \\hline 4. & 4. \\\\ \\hline 5. & 5. \\\\ \\hline \\end{array}$$
\\) 12 given: \\(\overline{jm} \cong \overline{nm}\\), \\(l\\) is the midpoint of \\(\overline{jn}\\) prove: \\(\triangle jlm \cong \triangle nlm\\) \\(\
$$\begin{array}{|c|c|} \\hline \\text{statements} & \\text{reasons} \\\\ \\hline 1. & 1. \\\\ \\hline 2. & 2. \\\\ \\hline 3. & 3. \\\\ \\hline 4. & 4. \\\\ \\hline 5. & 5. \\\\ \\hline \\end{array}$$
\\)
Problem 10 (Proving $\triangle LKM \cong \triangle LNM$)
Step 1: List Given Information
- Statement 1: $\overline{KM} \cong \overline{NM}$ (Given)
- Statement 2: $\overline{LK} \cong \overline{LN}$ (Given)
- Statement 3: $\overline{LM} \cong \overline{LM}$ (Reflexive Property of Congruence)
Step 2: Apply SSS Congruence
- Statement 4: $\triangle LKM \cong \triangle LNM$ (SSS Congruence Postulate, since all three corresponding sides are congruent)
- Reasons:
- Given
- Given
- Reflexive Property
- SSS Congruence Postulate
Problem 11 (Proving $\triangle ADC \cong \triangle ABC$)
Step 1: List Given Information
- Statement 1: $\overline{AD} \cong \overline{AB}$ (Given)
- Statement 2: $\overline{AC}$ bisects $\angle DAB$ (Given), so $\angle DAC \cong \angle BAC$ (Definition of Angle Bisector)
- Statement 3: $\overline{AC} \cong \overline{AC}$ (Reflexive Property of Congruence)
Step 2: Apply SAS Congruence
- Statement 4: $\triangle ADC \cong \triangle ABC$ (SAS Congruence Postulate, since two sides and the included angle are congruent)
- Reasons:
- Given
- Given; Definition of Angle Bisector
- Reflexive Property
- SAS Congruence Postulate
Problem 12 (Proving $\triangle JLM \cong \triangle NLM$)
Step 1: List Given Information
- Statement 1: $\overline{JM} \cong \overline{NM}$ (Given)
- Statement 2: $L$ is the midpoint of $\overline{JN}$, so $\overline{JL} \cong \overline{LN}$ (Definition of Midpoint)
- Statement 3: $\overline{LM} \cong \overline{LM}$ (Reflexive Property of Congruence)
Step 2: Apply SSS Congruence
- Statement 4: $\triangle JLM \cong \triangle NLM$ (SSS Congruence Postulate, since all three corresponding sides are congruent)
- Reasons:
- Given
- Given; Definition of Midpoint
- Reflexive Property
- SSS Congruence Postulate
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(for each problem's proof table):
Problem 10 Table:
| Statements | Reasons |
|---|---|
| 2. $\overline{LK} \cong \overline{LN}$ | 2. Given |
| 3. $\overline{LM} \cong \overline{LM}$ | 3. Reflexive Property |
| 4. $\triangle LKM \cong \triangle LNM$ | 4. SSS Congruence Postulate |
Problem 11 Table:
| Statements | Reasons |
|---|---|
| 2. $\angle DAC \cong \angle BAC$ | 2. Given ( $\overline{AC}$ bisects $\angle DAB$ ); Definition of Angle Bisector |
| 3. $\overline{AC} \cong \overline{AC}$ | 3. Reflexive Property |
| 4. $\triangle ADC \cong \triangle ABC$ | 4. SAS Congruence Postulate |
Problem 12 Table:
| Statements | Reasons |
|---|---|
| 2. $\overline{JL} \cong \overline{LN}$ | 2. Given ( $L$ is midpoint of $\overline{JN}$ ); Definition of Midpoint |
| 3. $\overline{LM} \cong \overline{LM}$ | 3. Reflexive Property |
| 4. $\triangle JLM \cong \triangle NLM$ | 4. SSS Congruence Postulate |