Question

10
8
6
12
2\sqrt{41}
\sqrt{181}

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(a = 8\), \(b = 10\), and \(c=j\) (hypotenuse). So \(j^{2}=10^{2}+8^{2}\).

Step2: Calculate \(j^{2}\)

\(j^{2}=100 + 64=164\).

Step3: Find \(j\)

\(j=\sqrt{164}=\sqrt{4\times41}=2\sqrt{41}\).

Answer:

\(2\sqrt{41}\)