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finding distances from the mean the mean of robins scores was 107. comp…

Question

finding distances from the mean
the mean of robins scores was 107. complete the chart to find the absolute distances from the mean for each of robins scores.

robins scoresdistance from the mean
1081
102x
107y
119z

x = y = z =

Explanation:

Step1: Calculate distance for 102

The formula for distance from the mean is \(|x - \text{mean}|\). Given mean = 107 and \(x = 102\), then \(x=|102 - 107|= 5\)

Step2: Calculate distance for 107

Given mean = 107 and \(y = 107\), then \(y=|107 - 107| = 0\)

Step3: Calculate distance for 119

Given mean = 107 and \(z = 119\), then \(z=|119 - 107|=12\)

Answer:

\(x = 5\)
\(y = 0\)
\(z = 12\)