QUESTION IMAGE
Question
finding distances from the mean
the mean of robins scores was 107. complete the chart to find the absolute distances from the mean for each of robins scores.
| robins scores | distance from the mean |
|---|---|
| 108 | 1 |
| 102 | x |
| 107 | y |
| 119 | z |
x = y = z =
Step1: Calculate distance for 102
The formula for distance from the mean is \(|x - \text{mean}|\). Given mean = 107 and \(x = 102\), then \(x=|102 - 107|= 5\)
Step2: Calculate distance for 107
Given mean = 107 and \(y = 107\), then \(y=|107 - 107| = 0\)
Step3: Calculate distance for 119
Given mean = 107 and \(z = 119\), then \(z=|119 - 107|=12\)
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\(x = 5\)
\(y = 0\)
\(z = 12\)