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1. grid fluff and fold charges $2.25 for each load of laundry. (lesson …

Question

  1. grid fluff and fold charges $2.25 for each load of laundry. (lesson 1)

a. draw the graph of the proportional relationship between the two quantities, where x is the number of loads of laundry and y is the total cost.
graph titled laundry with x-axis number of loads (0 - 9) and y-axis total cost ($) (0 - 9)
b. describe how the unit rate is represented in the graph.
box with 33.75 written

  1. open response daniella makes apple pies each fall. the cost at the local grocery store for x pounds of apples is shown in the table. what is the least amount of money daniella will spend for 15 pounds of apples? assume the relationship is proportional. (lesson 1)
number of pounds, xtotal cost ($), y
2$4.50
3$6.75

empty box

  1. multiple choice a turtle is crawling up a hill that rises 6 feet for every horizontal change of 36 feet. which of the following represents the slope of the hill, as a fraction in simplest form? (lesson 2)

a $\frac{6}{1}$ b $\frac{1}{6}$ c $\frac{36}{6}$ d $\frac{6}{36}$

  1. open response the points in the table lie on a line. compute the slope of the line. (lesson 2)
xy
6-3
-21
-42

box with $-\frac{1}{2}$ written

  1. multiselect which statement is true about the graph? select all that apply. (lesson 3)

graph with a line and triangles

  • the ratio of the rise to the run of each triangle is the same.
  • the smaller triangle and the larger triangle shown are similar.
  • the slope of the line is 2.
  • the slope of the line is -2.
  • the corresponding sides of the two triangles are not proportional.

module 4 • linear relationships and slope 249

Explanation:

Question 2 Solution (Open Response: Cost for 15 pounds of apples)

Step1: Find the unit rate (cost per pound)

The relationship is proportional, so we can find the unit rate using the given data. For \( x = 2 \) pounds, \( y = 4.50 \) dollars. The unit rate \( r \) is \( \frac{y}{x} \). So, \( r=\frac{4.50}{2}=2.25 \) dollars per pound. We can check with the other data: for \( x = 3 \) pounds, \( y = 6.75 \) dollars. \( \frac{6.75}{3}=2.25 \) dollars per pound, so the unit rate is consistent.

Step2: Calculate cost for 15 pounds

Now, to find the cost for 15 pounds, we use the formula \( y = r\times x \), where \( r = 2.25 \) and \( x = 15 \). So, \( y = 2.25\times15 \). Calculating that: \( 2.25\times15 = 33.75 \) dollars.

Step1: Recall the slope formula for a hill (rise over run)

Slope is defined as \( \text{slope}=\frac{\text{rise}}{\text{run}} \). The hill rises 6 feet (rise) for every horizontal change of 36 feet (run). So, the slope is \( \frac{6}{36} \).

Step2: Simplify the fraction

Simplify \( \frac{6}{36} \) by dividing both the numerator and the denominator by their greatest common divisor, which is 6. \( \frac{6\div6}{36\div6}=\frac{1}{6} \). Wait, no, wait: Wait, rise is vertical change (6 feet) and run is horizontal change (36 feet). Wait, actually, slope for a hill (a line) is rise over run, where rise is the vertical change (upward) and run is horizontal change (rightward). So, rise = 6, run = 36. So slope is \( \frac{6}{36}=\frac{1}{6} \)? Wait, no, wait the options: Option B is \( \frac{1}{6} \), but let's check again. Wait, the problem says "rises 6 feet for every horizontal change of 36 feet". So rise is 6, run is 36. So slope is \( \frac{6}{36}=\frac{1}{6} \)? Wait, but let's check the options. Wait, the options are A \( \frac{6}{1} \), B \( \frac{1}{6} \), C \( \frac{36}{6} \), D \( \frac{6}{36} \). But we need to simplify. \( \frac{6}{36}=\frac{1}{6} \), so the simplified form is \( \frac{1}{6} \), which is option B? Wait, no, wait: Wait, maybe I mixed up rise and run? Wait, no, slope is rise over run. Rise is vertical (6), run is horizontal (36). So slope is \( \frac{6}{36}=\frac{1}{6} \), which is option B. Wait, but let's check the options again. Wait, the problem says "as a fraction in simplest form". So \( \frac{6}{36} \) simplifies to \( \frac{1}{6} \), so the correct option is B.

Step1: Recall the slope formula between two points

The slope formula between two points \( (x_1,y_1) \) and \( (x_2,y_2) \) is \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Let's take two points from the table. Let's take \( (6, -3) \) and \( (-2, 1) \).

Step2: Apply the slope formula

Using \( (x_1,y_1)=(6, -3) \) and \( (x_2,y_2)=(-2, 1) \), we have \( m=\frac{1 - (-3)}{-2 - 6}=\frac{1 + 3}{-8}=\frac{4}{-8}=-\frac{1}{2} \). Let's check with another pair, say \( (-2, 1) \) and \( (-4, 2) \). Then \( m=\frac{2 - 1}{-4 - (-2)}=\frac{1}{-2}=-\frac{1}{2} \). So the slope is \( -\frac{1}{2} \).

Answer:

\( \$33.75 \)

Question 3 Solution (Multiple Choice: Slope of the hill)