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Question
- grid fluff and fold charges $2.25 for each load of laundry. (lesson 1)
a. draw the graph of the proportional relationship between the two quantities, where x is the number of loads of laundry and y is the total cost.
graph titled laundry with x-axis number of loads (0 - 9) and y-axis total cost ($) (0 - 9)
b. describe how the unit rate is represented in the graph.
box with 33.75 written
- open response daniella makes apple pies each fall. the cost at the local grocery store for x pounds of apples is shown in the table. what is the least amount of money daniella will spend for 15 pounds of apples? assume the relationship is proportional. (lesson 1)
| number of pounds, x | total cost ($), y |
| 2 | $4.50 |
| 3 | $6.75 |
empty box
- multiple choice a turtle is crawling up a hill that rises 6 feet for every horizontal change of 36 feet. which of the following represents the slope of the hill, as a fraction in simplest form? (lesson 2)
a $\frac{6}{1}$ b $\frac{1}{6}$ c $\frac{36}{6}$ d $\frac{6}{36}$
- open response the points in the table lie on a line. compute the slope of the line. (lesson 2)
| x | y |
| 6 | -3 |
| -2 | 1 |
| -4 | 2 |
box with $-\frac{1}{2}$ written
- multiselect which statement is true about the graph? select all that apply. (lesson 3)
graph with a line and triangles
- the ratio of the rise to the run of each triangle is the same.
- the smaller triangle and the larger triangle shown are similar.
- the slope of the line is 2.
- the slope of the line is -2.
- the corresponding sides of the two triangles are not proportional.
module 4 • linear relationships and slope 249
Question 2 Solution (Open Response: Cost for 15 pounds of apples)
Step1: Find the unit rate (cost per pound)
The relationship is proportional, so we can find the unit rate using the given data. For \( x = 2 \) pounds, \( y = 4.50 \) dollars. The unit rate \( r \) is \( \frac{y}{x} \). So, \( r=\frac{4.50}{2}=2.25 \) dollars per pound. We can check with the other data: for \( x = 3 \) pounds, \( y = 6.75 \) dollars. \( \frac{6.75}{3}=2.25 \) dollars per pound, so the unit rate is consistent.
Step2: Calculate cost for 15 pounds
Now, to find the cost for 15 pounds, we use the formula \( y = r\times x \), where \( r = 2.25 \) and \( x = 15 \). So, \( y = 2.25\times15 \). Calculating that: \( 2.25\times15 = 33.75 \) dollars.
Step1: Recall the slope formula for a hill (rise over run)
Slope is defined as \( \text{slope}=\frac{\text{rise}}{\text{run}} \). The hill rises 6 feet (rise) for every horizontal change of 36 feet (run). So, the slope is \( \frac{6}{36} \).
Step2: Simplify the fraction
Simplify \( \frac{6}{36} \) by dividing both the numerator and the denominator by their greatest common divisor, which is 6. \( \frac{6\div6}{36\div6}=\frac{1}{6} \). Wait, no, wait: Wait, rise is vertical change (6 feet) and run is horizontal change (36 feet). Wait, actually, slope for a hill (a line) is rise over run, where rise is the vertical change (upward) and run is horizontal change (rightward). So, rise = 6, run = 36. So slope is \( \frac{6}{36}=\frac{1}{6} \)? Wait, no, wait the options: Option B is \( \frac{1}{6} \), but let's check again. Wait, the problem says "rises 6 feet for every horizontal change of 36 feet". So rise is 6, run is 36. So slope is \( \frac{6}{36}=\frac{1}{6} \)? Wait, but let's check the options. Wait, the options are A \( \frac{6}{1} \), B \( \frac{1}{6} \), C \( \frac{36}{6} \), D \( \frac{6}{36} \). But we need to simplify. \( \frac{6}{36}=\frac{1}{6} \), so the simplified form is \( \frac{1}{6} \), which is option B? Wait, no, wait: Wait, maybe I mixed up rise and run? Wait, no, slope is rise over run. Rise is vertical (6), run is horizontal (36). So slope is \( \frac{6}{36}=\frac{1}{6} \), which is option B. Wait, but let's check the options again. Wait, the problem says "as a fraction in simplest form". So \( \frac{6}{36} \) simplifies to \( \frac{1}{6} \), so the correct option is B.
Step1: Recall the slope formula between two points
The slope formula between two points \( (x_1,y_1) \) and \( (x_2,y_2) \) is \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Let's take two points from the table. Let's take \( (6, -3) \) and \( (-2, 1) \).
Step2: Apply the slope formula
Using \( (x_1,y_1)=(6, -3) \) and \( (x_2,y_2)=(-2, 1) \), we have \( m=\frac{1 - (-3)}{-2 - 6}=\frac{1 + 3}{-8}=\frac{4}{-8}=-\frac{1}{2} \). Let's check with another pair, say \( (-2, 1) \) and \( (-4, 2) \). Then \( m=\frac{2 - 1}{-4 - (-2)}=\frac{1}{-2}=-\frac{1}{2} \). So the slope is \( -\frac{1}{2} \).
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\( \$33.75 \)