QUESTION IMAGE
Question
card sort
sort the cards into two groups based on whether they represent proportional relationships.
proportional relationship
not a proportional relationship
a
c
e
b
d
Step1: Recall the definition of proportional relationship
A proportional relationship has the form \(y = kx\) (where \(k\) is a constant) and passes through the origin \((0,0)\). For a table of values, \(\frac{y}{x}\) should be constant for non - zero \(x\) values.
Step2: Analyze Card A
For Card A:
When \(x = 4,y = 5\), \(\frac{y}{x}=\frac{5}{4}=1.25\)
When \(x = 8,y = 10\), \(\frac{y}{x}=\frac{10}{8}=1.25\)
When \(x = 12,y = 15\), \(\frac{y}{x}=\frac{15}{12}=1.25\)
And \((0,0)\) is present. So it is a proportional relationship.
Step3: Analyze Card B
For Card B:
When \(x = 2,y = 4\), \(\frac{y}{x}=\frac{4}{2}=2\)
When \(x = 4,y = 16\), \(\frac{y}{x}=\frac{16}{4}=4\)
The ratio \(\frac{y}{x}\) is not constant. So it is not a proportional relationship.
Step4: Analyze Card C
For Card C:
Since when \(x = 0,y = 2\) (does not pass through \((0,0)\)). So it is not a proportional relationship.
Step5: Analyze Card D
For Card D:
When \(x = 1,y = 10\), \(\frac{y}{x}=10\)
When \(x = 2,y = 8\), \(\frac{y}{x}=4\)
The ratio \(\frac{y}{x}\) is not constant. So it is not a proportional relationship.
Step6: Analyze Card E
For Card E:
When \(x = 2,y = 5\), \(\frac{y}{x}=\frac{5}{2}=2.5\)
When \(x = 8,y = 20\), \(\frac{y}{x}=\frac{20}{8}=2.5\)
When \(x = 1,y = 2.5\), \(\frac{y}{x}=2.5\)
When \(x = 20,y = 50\), \(\frac{y}{x}=\frac{50}{20}=2.5\)
So it is a proportional relationship.
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- Proportional Relationship: A, E
- Not a Proportional Relationship: B, C, D