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card sort sort the cards into two groups based on whether they represen…

Question

card sort
sort the cards into two groups based on whether they represent proportional relationships.
proportional relationship
not a proportional relationship
a
c
e
b
d

Explanation:

Step1: Recall the definition of proportional relationship

A proportional relationship has the form \(y = kx\) (where \(k\) is a constant) and passes through the origin \((0,0)\). For a table of values, \(\frac{y}{x}\) should be constant for non - zero \(x\) values.

Step2: Analyze Card A

For Card A:
When \(x = 4,y = 5\), \(\frac{y}{x}=\frac{5}{4}=1.25\)
When \(x = 8,y = 10\), \(\frac{y}{x}=\frac{10}{8}=1.25\)
When \(x = 12,y = 15\), \(\frac{y}{x}=\frac{15}{12}=1.25\)
And \((0,0)\) is present. So it is a proportional relationship.

Step3: Analyze Card B

For Card B:
When \(x = 2,y = 4\), \(\frac{y}{x}=\frac{4}{2}=2\)
When \(x = 4,y = 16\), \(\frac{y}{x}=\frac{16}{4}=4\)
The ratio \(\frac{y}{x}\) is not constant. So it is not a proportional relationship.

Step4: Analyze Card C

For Card C:
Since when \(x = 0,y = 2\) (does not pass through \((0,0)\)). So it is not a proportional relationship.

Step5: Analyze Card D

For Card D:
When \(x = 1,y = 10\), \(\frac{y}{x}=10\)
When \(x = 2,y = 8\), \(\frac{y}{x}=4\)
The ratio \(\frac{y}{x}\) is not constant. So it is not a proportional relationship.

Step6: Analyze Card E

For Card E:
When \(x = 2,y = 5\), \(\frac{y}{x}=\frac{5}{2}=2.5\)
When \(x = 8,y = 20\), \(\frac{y}{x}=\frac{20}{8}=2.5\)
When \(x = 1,y = 2.5\), \(\frac{y}{x}=2.5\)
When \(x = 20,y = 50\), \(\frac{y}{x}=\frac{50}{20}=2.5\)
So it is a proportional relationship.

Answer:

  • Proportional Relationship: A, E
  • Not a Proportional Relationship: B, C, D