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simplify the expression \\(\\frac{-b + \\sqrt{b^2 - 4ac}}{2a}\\) given …

Question

simplify the expression \\(\frac{-b + \sqrt{b^2 - 4ac}}{2a}\\) given that \\(a = 1\\), \\(b = -18\\), and \\(c = -3\\).

\\(\frac{-b + \sqrt{b^2 - 4ac}}{2a} = \square\\)
(simplify your answer. use integers or fractions for any numbers in the expression. type an exact answer, using radicals and \\(i\\) as needed.)

Explanation:

Substitute the given values into the expression

$$ LATEXBLOCK0 $$

Simplify the terms inside the radical and the denominator

$$ LATEXBLOCK1 $$

Simplify the radical and divide by the denominator

$$ LATEXBLOCK2 $$

Answer:

Simplify the expression \(\frac{-b + \sqrt{b^2 - 4ac}}{2a}\) given that \(a = 1\), \(b = -18\), and \(c = -3\).

\(\frac{-b + \sqrt{b^2 - 4ac}}{2a} =\) <blank>\(9 + 2\sqrt{21}\)</blank>