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Question
simplify the expression \\(\frac{-b + \sqrt{b^2 - 4ac}}{2a}\\) given that \\(a = 1\\), \\(b = -18\\), and \\(c = -3\\).
\\(\frac{-b + \sqrt{b^2 - 4ac}}{2a} = \square\\)
(simplify your answer. use integers or fractions for any numbers in the expression. type an exact answer, using radicals and \\(i\\) as needed.)
Substitute the given values into the expression
$$
LATEXBLOCK0
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Simplify the terms inside the radical and the denominator
$$
LATEXBLOCK1
$$
Simplify the radical and divide by the denominator
$$
LATEXBLOCK2
$$
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Simplify the expression \(\frac{-b + \sqrt{b^2 - 4ac}}{2a}\) given that \(a = 1\), \(b = -18\), and \(c = -3\).
\(\frac{-b + \sqrt{b^2 - 4ac}}{2a} =\) <blank>\(9 + 2\sqrt{21}\)</blank>