position vs. time graphs
the following questions refer to the position vs. time graph below.

30. when did the person begin moving?
a. 0 sec
b. 1 sec
c. 2 sec
d. 9 sec
31. for how long does the person move away from their original position?
a. 1 sec
b. 2 sec
c. 3 sec
d. 4 sec
32. after the person starts moving, they stop for a little bit. how long do they stop?
a. 1 sec
b. 2 sec
c. 3 sec
d. 8 sec
33. what is the total amount of time that this person is moving?
a. 2 sec
b. 4 sec
c. 6 sec
d. 8 sec
e. 10 sec
34. what is the persons speed between 1 and 4 seconds?
a. 1 m/s
b. 2 m/s
c. 3 m/s
d. 1.5 m/s
study the quizizz/blookets/gimkits and ck-12 assignments that are on google
classroom as well as all of your calculation problems. i will be pulling questions from all
of these for your test.

Question

position vs. time graphs
the following questions refer to the position vs. time graph below.

30. when did the person begin moving?
 a. 0 sec
 b. 1 sec
 c. 2 sec
 d. 9 sec
31. for how long does the person move away from their original position?
 a. 1 sec
 b. 2 sec
 c. 3 sec
 d. 4 sec
32. after the person starts moving, they stop for a little bit. how long do they stop?
 a. 1 sec
 b. 2 sec
 c. 3 sec
 d. 8 sec
33. what is the total amount of time that this person is moving?
 a. 2 sec
 b. 4 sec
 c. 6 sec
 d. 8 sec
 e. 10 sec
34. what is the persons speed between 1 and 4 seconds?
 a. 1 m/s
 b. 2 m/s
 c. 3 m/s
 d. 1.5 m/s
study the quizizz/blookets/gimkits and ck-12 assignments that are on google
classroom as well as all of your calculation problems. i will be pulling questions from all
of these for your test.

Accepted Answer

# Explanation:
## 30.
### Step1: Analyze the graph
A person starts moving when the position - time graph has a non - zero slope. At $t = 1$ sec, the slope of the graph becomes non - zero (before $t = 1$ sec, the position is $0$ and there is no change).

## 31.
### Step1: Determine the time interval of moving away
The person moves away from the original position (where position $x = 0$) when the slope of the position - time graph is positive. The time interval for positive slope is from $t = 1$ sec to $t=4$ sec. The duration is $4 - 1=3$ sec.

## 32.
### Step1: Identify the time of zero slope (after starting)
After starting (after $t = 1$ sec), the graph has a zero slope (horizontal line) from $t = 4$ sec to $t = 6$ sec. The duration is $6 - 4 = 2$ sec.

## 33.
### Step1: Calculate the total moving time
The moving time is the sum of the time intervals with non - zero slope. The intervals are $1 - 4$ sec ($3$ sec) and $6 - 9$ sec ($3$ sec). Total moving time $3+3 = 6$ sec.

## 34.
### Step1: Use the speed formula $v=\frac{\Delta x}{\Delta t}$
Between $t = 1$ sec and $t = 4$ sec, $\Delta x=6 - 0=6$ m and $\Delta t=4 - 1 = 3$ sec. Then $v=\frac{6}{3}=2$ m/s.

# Answer:
30. b. 1 sec
31. c. 3 sec
32. b. 2 sec
33. c. 6 sec
34. b. 2 m/s

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

30.

Step1: Analyze the graph

31.

Step1: Determine the time interval of moving away

32.

Step1: Identify the time of zero slope (after starting)

33.

Step1: Calculate the total moving time

34.

Step1: Use the speed formula \(v=\frac{\Delta x}{\Delta t}\)

Answer: