Question

convert the following expression to radical form.

\\z^{\frac{1}{9}}\\

\\\sqrt?{z^{\square}}\\

Explanation:

Identify the given expression

The problem asks us to convert the exponential expression \(z^{\frac{1}{9}}\) into its equivalent radical form.

Recall the definition of rational exponents

A rational exponent of the form \(\frac{m}{n}\) represents a radical operation. The general conversion rule is:

$$x^{\frac{m}{n}} = \sqrt[n]{x^m}$$

where \(n\) is the index of the radical and \(m\) is the power of the radicand.

Apply the conversion rule

For the given expression \(z^{\frac{1}{9}}\):

• The base is \(z\).
• The numerator of the exponent is \(m = 1\).
• The denominator of the exponent is \(n = 9\).

Substituting these values into the rule gives:

$$z^{\frac{1}{9}} = \sqrt[9]{z^1} = \sqrt[9]{z}$$

Determine the missing value

The question shows a template with a green box containing a question mark \([?]\) as the index of the radical:

$$\sqrt[[?]]{z^{\Box}}$$

Comparing this template to our result \(\sqrt[9]{z^1}\), the index in the position of \([?]\) must be \(9\).

Answer:

Convert the following expression to radical form.
\(z^{\frac{1}{9}} =\) <blank>\(\sqrt[9]{z}\)</blank>