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Question
choose the inverse of \\(y = x^2 - 10x\\).
\\(y = \pm\sqrt{x - 25} - 5\\)
\\(y = \pm\sqrt{x - 25} + 5\\)
\\(y = \pm\sqrt{x + 25} - 5\\)
\\(y = \pm\sqrt{x + 25} + 5\\)
Swap variables to set up the inverse relation
$$
x = y^2 - 10y
$$
Complete the square for the quadratic expression in terms of y
$$
LATEXBLOCK0
$$
Solve for y using the square root property
$$
LATEXBLOCK1
$$
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- (A) \(y = \pm\sqrt{x - 25} - 5\)
- (B) \(y = \pm\sqrt{x - 25} + 5\)
- (C) \(y = \pm\sqrt{x + 25} - 5\)
- (D) \(y = \pm\sqrt{x + 25} + 5\) (Correct answer)