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choose the inverse of \\(y = x^2 - 10x\\). \\(y = \\pm\\sqrt{x - 25} - …

Question

choose the inverse of \\(y = x^2 - 10x\\).

\\(y = \pm\sqrt{x - 25} - 5\\)

\\(y = \pm\sqrt{x - 25} + 5\\)

\\(y = \pm\sqrt{x + 25} - 5\\)

\\(y = \pm\sqrt{x + 25} + 5\\)

Explanation:

Swap variables to set up the inverse relation

$$ x = y^2 - 10y $$

Complete the square for the quadratic expression in terms of y

$$ LATEXBLOCK0 $$

Solve for y using the square root property

$$ LATEXBLOCK1 $$

Answer:

  • (A) \(y = \pm\sqrt{x - 25} - 5\)
  • (B) \(y = \pm\sqrt{x - 25} + 5\)
  • (C) \(y = \pm\sqrt{x + 25} - 5\)
  • (D) \(y = \pm\sqrt{x + 25} + 5\) (Correct answer)