Question

write the orbital notation for the following elements:
fluorine (f)
element
name and
symbol
number
of
electrons
orbital notation

Explanation:

Step1: Determine the atomic number of Fluorine

The atomic number of Fluorine (\(F\)) is \(9\). So the number of electrons is also \(9\) (for a neutral atom, number of electrons = atomic number).

Step2: Write the orbital notation

• The \(1s\) orbital: It can hold a maximum of \(2\) electrons. So we have \(1s^{2}\).
• The \(2s\) orbital: It can hold a maximum of \(2\) electrons. So we have \(2s^{2}\).
• The \(2p\) orbital: It can hold a maximum of \(6\) electrons. But we have \(9-(2 + 2)=5\) electrons left for the \(2p\) orbital. So we have \(2p^{5}\).

Combining these, the orbital notation for Fluorine is \(1s^{2}2s^{2}2p^{5}\).

Answer:

Symbol: \(F\); Number of Electrons: \(9\); Orbital Notation: \(1s^{2}2s^{2}2p^{5}\)