Question

write full electron configurations for sb. express your answer in complete form in order of increasing orbital energy as a string without blank space between orbitals. for example, 1s²2s² should be entered as 1s^22s^2.

Explanation:

Step1: Determine the atomic number of Sb

The atomic number of Sb (antimony) is \(51\).

Step2: Fill the orbitals according to the Aufbau principle

Start filling orbitals in the order \(1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p\).

• \(1s\) can hold \(2\) electrons: \(1s^2\)
• \(2s\) can hold \(2\) electrons: \(2s^2\)
• \(2p\) can hold \(6\) electrons: \(2p^6\)
• \(3s\) can hold \(2\) electrons: \(3s^2\)
• \(3p\) can hold \(6\) electrons: \(3p^6\)
• \(4s\) can hold \(2\) electrons: \(4s^2\)
• \(3d\) can hold \(10\) electrons: \(3d^{10}\)
• \(4p\) can hold \(6\) electrons: \(4p^6\)
• \(5s\) can hold \(2\) electrons: \(5s^2\)
• \(4d\) can hold \(10\) electrons: \(4d^{10}\)
• \(5p\) needs \(3\) electrons (since \(2 + 2+6 + 2+6 + 2+10 + 6+2 + 10=48\), and \(51 - 48 = 3\)): \(5p^3\)

Answer:

\(1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^3\)