Question

write full electron configurations for n. express your answer in complete form in order of increasing orbital energy as a string without blank space between orbitals. for example, 1s²2s² should be entered as 1s^22s^2.

Explanation:

Step1: Determine the atomic number of N

The atomic number of nitrogen (N) is 7. This means a neutral N atom has 7 electrons.

Step2: Fill the orbitals according to the Aufbau principle

• First, fill the 1s orbital. The 1s orbital can hold 2 electrons: \(1s^{2}\).
• Then, fill the 2s orbital. The 2s orbital can hold 2 electrons: \(2s^{2}\).
• After that, fill the 2p orbital. We have \(7-(2 + 2)=3\) electrons left for the 2p orbital. The 2p orbital can hold up to 6 electrons. So we get \(2p^{3}\).

Answer:

1s^22s^22p^3