write formulas for the compounds formed from rb and each of the following polyatomic ions: no₂⁻, co₃²⁻, po₄³⁻. express your answers as chemical formulas separated by commas.

Question

Accepted Answer

# Explanation:
## Step1: Determine the charge of Rb
Rubidium (Rb) is an alkali metal, so it forms a $+1$ ion ($Rb^+$).

## Step2: Combine with $NO_2^-$
The charge of $NO_2^-$ is $-1$. To balance the charges, we need 1 $Rb^+$ and 1 $NO_2^-$. So the formula is $RbNO_2$.

## Step3: Combine with $CO_3^{2-}$
The charge of $CO_3^{2-}$ is $-2$. We need 2 $Rb^+$ (each $+1$) to balance the $-2$ charge. So the formula is $Rb_2CO_3$.

## Step4: Combine with $PO_4^{3-}$
The charge of $PO_4^{3-}$ is $-3$. We need 3 $Rb^+$ (each $+1$) to balance the $-3$ charge. So the formula is $Rb_3PO_4$.

# Answer:
$RbNO_2$, $Rb_2CO_3$, $Rb_3PO_4$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Determine the charge of Rb

Step2: Combine with \(NO_2^-\)

Step3: Combine with \(CO_3^{2-}\)

Step4: Combine with \(PO_4^{3-}\)

Answer: