Question

write the concentration equilibrium constant expression for this reaction. cu^{2+}(aq)+2ag(s)→cu(s)+2ag^{+}(aq)

Explanation:

Step1: Recall the formula for equilibrium constant

For a reaction \(aA + bB
ightleftharpoons cC + dD\), \(K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}\), where \(A,B\) are reactants and \(C,D\) are products. Solids (\(s\)) and pure liquids (\(l\)) are excluded from the expression.

Step2: Identify reactants and products in the given reaction

In the reaction \(\ce{Cu^{2+}(aq) + 2Ag(s)\to Cu(s) + 2Ag^{+}(aq)}\), the reactant in aqueous state is \(\ce{Cu^{2+}}\) and the product in aqueous state is \(\ce{Ag^{+}}\).

Step3: Write the equilibrium constant expression

Using the formula from Step1, with \(a = 1\) (for \(\ce{Cu^{2+}}\)), \(d=2\) (for \(\ce{Ag^{+}}\)), and excluding the solids (\(\ce{Ag}\) and \(\ce{Cu}\)), we get \(K_c=\frac{[\ce{Ag^{+}}]^2}{[\ce{Cu^{2+}}]}\)

Answer:

\(K_c=\frac{[\ce{Ag^{+}}]^2}{[\ce{Cu^{2+}}]}\)