Question

write the complete ground - state electron configuration of titanium. for multi - digit superscripts or coefficients, use each number in succession.

Explanation:

Step1: Determine the atomic number of titanium

Titanium has an atomic number \( Z = 22 \).

Step2: Fill the orbitals according to the Aufbau principle

Start filling orbitals in the order \( 1s<2s < 2p<3s<3p<4s<3d\).

• \(1s\) orbital: can hold \(2\) electrons, so \(1s^{2}\)
• \(2s\) orbital: can hold \(2\) electrons, so \(2s^{2}\)
• \(2p\) orbital: can hold \(6\) electrons, so \(2p^{6}\)
• \(3s\) orbital: can hold \(2\) electrons, so \(3s^{2}\)
• \(3p\) orbital: can hold \(6\) electrons, so \(3p^{6}\)
• \(4s\) orbital: can hold \(2\) electrons, so \(4s^{2}\)
• After filling \(4s\), we fill \(3d\). We have \(22-(2 + 2+6 + 2+6 + 2)=2\) electrons left for \(3d\), so \(3d^{2}\)

Answer:

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{2}\)