Question

write the complete ground - state electron configuration of ti²⁺. for multi - digit superscripts or coefficients, use each number in succession.

Explanation:

Step1: Determine the atomic number of Ti

The atomic number of Ti (titanium) is \( Z = 22 \). So, a neutral Ti atom has 22 electrons.

Step2: Write the electron configuration of neutral Ti

Using the Aufbau principle (\( 1s<2s < 2p<3s<3p < 4s<3d\)), the electron configuration of \( Ti\) is \( 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{2}\).

Step3: Consider the ion formation

\( Ti^{2 +}\) is formed by losing 2 electrons. Electrons are lost from the highest - energy orbital first. The \( 4s\) orbital has a higher energy than the \( 3d\) orbital for transition - metal ions. So, we remove 2 electrons from the \( 4s\) orbital.

Answer:

\( 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{2}\)