Question

write the chemical symbols for three different atoms or atomic anions with 36 electrons.

Explanation:

Step1: Recall the relationship between electrons and atomic number for neutral atoms

For a neutral atom, the number of electrons is equal to the atomic number. The element with atomic number \(36\) is krypton (\(Kr\)).

Step2: Consider anions (negatively - charged ions)

Anions gain electrons. Bromine (\(Br\)) has an atomic number of \(35\). When it gains one electron (\(Br^-\)), the number of electrons is \(35 + 1=36\).

Step3: Consider another anion

Selenium (\(Se\)) has an atomic number of \(34\). When it gains two electrons (\(Se^{2 -}\)), the number of electrons is \(34+2 = 36\).

Answer:

\(Kr\), \(Br^-\), \(Se^{2 -}\)