Question

write the chemical symbol for the isotope of cobalt with 37 neutrons. 250 words remaining

Explanation:

Step1: Determine the atomic number of cobalt

Cobalt (\(Co\)) has an atomic number (\(Z\)) of \(27\) (from the periodic table).

Step2: Calculate the mass number (\(A\))

Mass number \(A=Z + N\), where \(N\) is the number of neutrons. Given \(N = 37\) and \(Z=27\), then \(A=27 + 37=64\).

Step3: Write the isotope symbol

The general form of an isotope symbol is \(^{A}_{Z}X\), where \(X\) is the element symbol. For cobalt (\(X = Co\)), \(Z = 27\) and \(A = 64\), so the symbol is \(^{64}_{27}Co\).

Answer:

\(^{64}_{27}Co\)