Question

write the balanced net ionic equation for the reaction when hi and sr(oh)₂ are mixed in aqueous solution. if no reaction occurs, simply write only nr. be sure to include the proper phases for all species within the reaction.

Explanation:

Step1: Write the molecular equation

Hydroiodic acid (\(HI\)) reacts with strontium hydroxide (\(Sr(OH)_2\)). The molecular equation is \(2HI(aq)+Sr(OH)_2(aq)\to SrI_2(aq) + 2H_2O(l)\)

Step2: Dissociate strong electrolytes

\(HI\) is a strong acid (\(HI(aq)\to H^{+}(aq)+I^{-}(aq)\)), \(Sr(OH)_2\) is a strong base (\(Sr(OH)_2(aq)\to Sr^{2 +}(aq)+2OH^{-}(aq)\)), \(SrI_2\) is a soluble salt (\(SrI_2(aq)\to Sr^{2+}(aq)+2I^{-}(aq)\))

Step3: Write the total ionic equation

\(2H^{+}(aq)+2I^{-}(aq)+Sr^{2 +}(aq)+2OH^{-}(aq)\to Sr^{2+}(aq)+2I^{-}(aq)+2H_2O(l)\)

Step4: Cancel out spectator ions

Spectator ions are \(Sr^{2+}\) and \(I^{-}\). The net - ionic equation is \(H^{+}(aq)+OH^{-}(aq)\to H_2O(l)\)

Answer:

\(H^{+}(aq)+OH^{-}(aq)\to H_2O(l)\)