Question

write a balanced chemical equation based on the following description: solid potassium oxide reacts with liquid water to produce aqueous potassium hydroxide k₂o(s) + h₂o(l) →

Explanation:

Step1: Write the unbalanced equation

The reaction is \(K_{2}O(s)+H_{2}O(l)\to KOH(aq)\)

Step2: Balance the potassium atoms

On the left - hand side, there are 2 potassium atoms in \(K_{2}O\). On the right - hand side, there is 1 potassium atom in \(KOH\). So, we put a coefficient of 2 in front of \(KOH\): \(K_{2}O(s)+H_{2}O(l)\to 2KOH(aq)\)

Step3: Check the balance of oxygen and hydrogen atoms

For oxygen:
Left - hand side: \(1\) (from \(K_{2}O\)) \(+ 1\) (from \(H_{2}O\)) \(= 2\)
Right - hand side: \(2\) (from \(2KOH\))
For hydrogen:
Left - hand side: \(2\) (from \(H_{2}O\))
Right - hand side: \(2\) (from \(2KOH\))

Answer:

\(K_{2}O(s)+H_{2}O(l)=2KOH(aq)\)