Question

which lewis electron - dot diagram represents an oxygen - 16 atom in the ground state?

Explanation:

A Lewis electron - dot diagram shows the valence electrons of an atom. Oxygen has an atomic number of 8. The electron configuration is \(1s^{2}2s^{2}2p^{4}\). The valence shell is the second shell (\(n = 2\)), and the number of valence electrons is \(2 + 4=6\). In a Lewis electron - dot diagram, we represent the atom's symbol (O for oxygen) and place dots around it to represent the valence electrons. We place the dots one at a time on the four sides (up, down, left, right) of the symbol and then pair them up after each side has one dot. For 6 valence electrons, we have two pairs and two unpaired electrons.

Answer:

A.