Question

q 6. which of the following is the metallic ion in sodium fluoride?

f 2+

na 1-

f 2-

na 1+

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Explanation:

Sodium fluoride ($\ce{NaF}$) is an ionic compound. Sodium ($\ce{Na}$) is a metal. In ionic compounds, metals lose electrons to form cations. Sodium has a tendency to lose one electron to achieve a stable electron configuration, forming the $\ce{Na^{+}}$ (sodium ion). Fluorine ($\ce{F}$) is a non - metal and gains one electron to form the $\ce{F^{-}}$ (fluoride ion). The options $\ce{F^{2+}}$ and $\ce{F^{2 - }}$ are incorrect as fluorine typically forms $\ce{F^{-}}$ (gains one electron). $\ce{Na^{-}}$ is incorrect as sodium loses one electron (not gains) to form a cation.

Answer:

$\ce{Na^{+}}$ (the option corresponding to $\ce{Na^{+}}$ in the given multiple - choice list)