Question

which of the following inequalities is graphed on the coordinate plane?

\\(y < -3x + 5\\)
\\(y > -3x + 5\\)
\\(y \le -3x + 5\\)
\\(y \ge -3x + 5\\)

Explanation:

Identify the boundary line equation

Using the Linear Functions knowledge point

$$
LATEXBLOCK0
$$

Determine the inequality sign

The boundary line is dashed, which means the inequality is strict (\(<\) or \(>\)).
The shaded region is below and to the left of the line.
Testing the origin \((0,0)\):

$$ 0 < -3(0) + 5 \implies 0 < 5 \quad (\text{True}) $$

Thus, the correct inequality is \(y < -3x + 5\).

Answer:

• (A) \(y < -3x + 5\) (Correct answer)
• (B) \(y > -3x + 5\)
• (C) \(y \le -3x + 5\)
• (D) \(y \ge -3x + 5\)