Question

which of the following compounds are ionic compounds? check all of the boxes that apply. cacl₂ c₆h₁₂o₆ mgo na₂o sio₂ done

Explanation:

Step1: Determine the electronegativity difference

For \(CaCl_{2}\):
The electronegativity of \(Ca = 1.0\) and \(Cl=3.2\).
The difference \(\Delta EN=|3.2 - 1.0|=2.2\)

For \(C_{6}H_{12}O_{6}\):
It is a covalent compound (organic compound with non - metal - non - metal bonds). For example, \(C - H\) bond: \(\Delta EN=|2.6 - 2.1| = 0.5\), \(C - O\) bond: \(\Delta EN=|3.4 - 2.6|=0.8\)

For \(MgO\):
The electronegativity of \(Mg = 1.3\) and \(O = 3.4\).
The difference \(\Delta EN=|3.4 - 1.3|=2.1\)

For \(Na_{2}O\):
The electronegativity of \(Na=0.9\) and \(O = 3.4\).
The difference \(\Delta EN=|3.4 - 0.9|=2.5\)

For \(SiO_{2}\):
The electronegativity of \(Si = 1.9\) and \(O=3.4\).
The difference \(\Delta EN=|3.4 - 1.9|=1.5\)

Step2: Use the rule for ionic compounds

A compound is considered ionic if the electronegativity difference \(\Delta EN>1.7\)

Answer:

\(CaCl_{2}\), \(MgO\), \(Na_{2}O\)